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第12章 三相电路
一、选择题
如图12-1所示为对称三相电路,电源线电压U1=1OOV,线电流I1=2A,负载功率因数λ=cosφ=0.8(感性),功率表接法也如图所示,则此时功率表读数为( )。[上海交通大学2005研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image437.jpg?sign=1739027667-JAN3BrkHkVlQ6yrGzw1Dhb9xUi26UsIW-0-86fb7943b68c934bf76e4a90c4a637c3)
图12-1
A.208W
B.120W
C.173W
D.0
【答案】A
【解析】选为参考相量,
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image440.jpg?sign=1739027667-CBEreUCNrW9o8cqlhRYcqQsuSTj8DwTU-0-eaba3bb5c6f791ce6c4300cfc2baf5f3)
二、填空题
1.在如图12-2所示的对称三相正弦交流电路中,所有三只安培表的读数都是10A,如果外加三相对称线电压保持不变,而将AB相负载断开,则电流表A1的读数为_____,电流表A2的读数为_____,电流表A3的读数为_____。[浙江大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image441.jpg?sign=1739027667-LLLGBIkeDgtVr267xSsf4Y5UEwY155Mx-0-8f0c3bc446e3955d12b718f1b3dca6c1)
图12-2
【答案】5.77A; 5.77A; 10A
【解析】按一般正弦稳态电路分析方法即可得出结果。
2.图12-3所示三相对称电路中开关S合上时电流表A1的读数是A,则开关S合上时电流表A2的读数是( );A3的读数是( );开关S断开时电流表A1的读数是( );A2的读数是( );A3的读数是( )。[华南理工大学2010研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image443.jpg?sign=1739027667-IlGzLu3PZtw1PHEITt7ddqpUth25RzE3-0-6eb8e700ea42b303a1184dbac3193909)
图12-3
【答案】;
;
;10A;10A
【解析】根据三相电路的对称性,在开关闭合后,三表读数是相同的,即都是;在开关打开之后,
读数不变认为
,
和
的电流表读数变化,线电流变为相电流,为10A。
3.某三角形联接的电力负载,线电压、
及
严重不对称且含有5、7次谐波,该三相负载线电压的零序分量为( )。[华南理工大学2009研]
【答案】
【解析】将不对称的三相线电压分解为三组对称的相量,分别为正序分量、负序分量和零序分量。由于三相线电压中各相对应的正序分量相量和为0、负序分量相量和为0,并且各谐波分量只含有交流分量(即正序、零序分量),无零序分量。则三相线电压的相量和即为三倍的零序分量。即有:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image452.png?sign=1739027667-3lCokRMaK0eZY8y5Tlohnhu8yJpFrXvp-0-e68b49946913740dd0b47021b30a780a)
4.如图12-4所示对称三相电路中,已知星形连接负载(复)阻抗Z=5+j8.66Ω,若已测得电路无功功率
图12-4
【答案】由Z=5+j8.66Ω可得阻抗角为
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image455.jpg?sign=1739027667-NlPPgpUJbTRgthbTzB9Ms3qy86HWHRxA-0-e68667316a2a6295b72fd7d2298523f9)
于是有功功率为
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image456.jpg?sign=1739027667-pxQKYtdztDSxhg3x9kVU9rzwjcz8kcGd-0-a5fbb58a741433a91cda50ea172fc1de)
三、计算题
1.线电压为
的三相电源上接有两组对称三相负载:一组是三角形联结的电感性负载,每相阻抗
;另一组是星形联结的电阻性负载,每相电阻
,如图12-5所示。试求:(1)各组负载的相电流;(2)电路线电流;(3)三相有功功率。[西南大学2012研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image461.jpg?sign=1739027667-WLCUpgJsfWpKhYU7IE7ECojWbAgcPBlB-0-dfeb8109955664fa82c28100f1af9bb9)
图12-5
解:设。
(1)对于星形负载,线电流等于相电流,为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image463.png?sign=1739027667-oAYKYD5XoV0is697ZlI1yL8WqwtXfM9H-0-decaee5cb2fedbb774088b5638bba635)
星形负载消耗有功为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image464.png?sign=1739027667-bsDsAUvDucqfL3mYRonLnoKcmWeLXb1z-0-fe91bd326a3b4c6e31a07a31739d9865)
对于三角形联结的负载,相电流为线电流的倍。将三角形联结等效为星形联结。得相电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image466.png?sign=1739027667-cfYrMe0EeHBn4EeHzv0ssEERLlWAiOMU-0-9f5aa3d87ebe9b5a5d9b3bafb45d32b5)
线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image467.png?sign=1739027667-sUG6gTulTGOXufPn1tjB6MVEHkpbDaK6-0-ac7c4dddc2f3068d6886ed2204adbe3b)
(2)电路线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image468.png?sign=1739027667-vQepmVWaGbn4VYwH664qmoC7pI5VUvEU-0-03b3428eee4604cf16ba56fad54ee26e)
(3)三角形联结负载消耗有功为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image469.png?sign=1739027667-Lh4keHXuOfkKgXVrwc3VUVcTEgeq5abm-0-b75c885ae2fe37794a65f1dd83e54cff)
则总三相有功功率为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image470.png?sign=1739027667-7O2FagieA8baOYDhKKqUtVmrcxNQgNgU-0-060fe783e192f4e8088756b2103296f0)
2.图12-6(a)所示的对称三相电路中,三相电源线电压U1=300V,三相角接负载阻抗(容性)吸收功率P=4500W,三相电源供出的功率PS=7200W,线路阻抗Z1=(3+j3)Ω。试求线电流I1和负载阻抗Z。[天津大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image471.jpg?sign=1739027667-Qyp4saL9spWmBHMzxAYMfR2nALBepJRY-0-d3571a11552bd44307f7b7eb472f7c46)
图12-6
解:由已知条件,线路阻抗消耗的平均功率为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image473.png?sign=1739027667-5tRNOd9exaVAaxdUMfkKUfcyR1hxkHVU-0-9b86b5c892baf35bd4a58b6d3b70cf14)
则三相电路的线电流为:
将△形负载等效成Y形负载,并取其一相得图(b)所示电路,其中:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image475.jpg?sign=1739027667-VmiI35CC2knK2tn8bEEyY5YRxIkIlRlA-0-b0d750922a85e3fbda272e8c0c69d07e)
在图(b)中,相电流等于原电路的线电流。
再由负载消耗功率可知实部为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image477.jpg?sign=1739027667-vvJep4UXwtbFxIRWBZ0Ggz66IZZlmhb5-0-7616c2575f1bdeb2df2587e9ce2d9edd)
由题知,负载阻抗为容性,则有:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image478.jpg?sign=1739027667-4cF1PzlKrBgHhJoxdtj9ACCGy1QHycXf-0-0504601faa9eb5e23fb33281aaf53fca)
解得:XY=9Ω
则△形负载阻抗为:。
3.如图12-7所示对称三相电路中,对称三相电源频率为50Hz,线电压为380V,对称三相负载Z=(18+j24)Ω,对称三相电容负载C=58μF。试求:(1)各线电流;(2)电源发出的复功率。[北京交通大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image480.jpg?sign=1739027667-ef22XerxyHk9shmBIIwgf7xTYGthnPlK-0-839b93685180dded3b96658bf2e9687d)
图12-7
解:(1)已知电源线电压为380V,可知相电压(这里设定A相相电压相角为):
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image482.png?sign=1739027667-0XihUFuKrVTnTh5XjZLXek8VYC24Cd8X-0-43565c07e06d46b04cc5420b7f65ef1a)
V
V
A
A
A
再由对称性可得、
:
A
A
(2)三相电源的复功率为
V·A
4.图12-8中A、B、C为对称三相电源,已知
图12-8
解:因为A、B、C为对称三相电源,所以
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image495.jpg?sign=1739027667-K6DUH95LOoHINXQPTMo8hpa8bv8c0M52-0-de24157499ac1b2241bd98d65ab7ed83)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image496.jpg?sign=1739027667-S9OhHZ8xeHE2Tu9LKdiGXBAIx0Umo2Sz-0-1be1da89524684799190d171ef207208)
先求阻抗Z的模值:
由题、
都闭合时,三个电流表读数均为5A,则有:
,解得
=132
。
(1)当开关S1闭合、S2断开时,A1、A2、A3的读数分别为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image502.png?sign=1739027667-p3ymhn98cuepw4K54dbGF5d1P3UaGHpo-0-0dbc31b919275566f7aa447d9e486e11)
由对称性知A
不变,即
A
(2)当开关S1断开、S2闭合时,A1、A2、A3的读数分别为:
A
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image507.png?sign=1739027667-z7onAPJhLHyIGPd5mu8ltFmMuzTBgb0s-0-951f2df8ac0b52a3c1ebeb3cd98dbd22)
A
5.如图12-9所示电路中,已知对称三相电压源线电压为380V,两组对称负载。第一组负载均为,第二组负载均为
,求:(1)电流表A1、A2、A3的示数;(2)当第二组A相负载发生短路故障后,电流表A1、A2、A3的示数;(3)当第二组A相负载发生断路故障后,电流表A1、A2、A3的示数。[北京交通大学2010研]
图12-9
解:(1)进行变换,得
。令
。
对于电流表A1:,故A1的示数为
A。
对于电流表A3:由,故A3的示数为11A。
对于电流表A2:,又
,
,
,所以
,故A2的示数为
A。
(2)对于电流表A3:,故A3的示数为
A。
对于电流表A2:,故A2的示数为26.9A。
对于电流表A1:设,则
,
,由此可得
,故
。
又,所以:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image533.png?sign=1739027667-uK7PSFEkLHxEiWCpVjWyXd2CK7LdmaMh-0-fed7201a0808093d0b08bd23a207d548)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image535.png?sign=1739027667-AICKUrag9UaJFH9dCF4lvVx3KgLXzWOB-0-d6a99b9c39415ac81a9b1b0605c9b8a9)
因此,A1的示数为65.1A。
(3)对于电流表A1:,故A1的示数为46.5A。
对于电流表A2:,故A2的示数为26.9A。
对于电流表A3:,故A3的示数为9.5A。
6.图12-10所示三相对称电路,已知电压表的读数为,负载阻抗
,线路阻抗
,求图中电流表的读数和线电压UAB。[北京科技大学2011研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image542.jpg?sign=1739027667-49J94xcB85r0aYEk1lhKnNOhCjm0tE3h-0-14bec63bec06f87f6ce730ae5ed9025f)
图12-10
解:(1)根据对称线电压和对称相电压之间的关系,可得对称相电压
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image543.png?sign=1739027667-uw1FIiUnqekT5cPJcezivkvON4t7FGf1-0-834e968ab1bb2325d05d426a97336569)
则有
A
则电流表的示数为16.67A
(2)则
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image546.png?sign=1739027667-V9H6rUOvkxoywtGmjn2WMAStadgNnq8s-0-9d61d35e22a49137cd122898ebdb3476)
7.已知如图12-11所示电路中对称三相电源线电压V,阻抗Z1=50+j50Ω,Z2=20Ω,Z3=40+j80Ω,中线电阻R=3Ω。
(1)求图示功率表的读数;
(2)求A相电源uA发出的有功功率和无功功率。[清华大学2005研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image548.png?sign=1739027667-A2SwR7UVDjI2NXG9FTjpWYQ4YOTp2xnd-0-e9e54acbd623165440e1ed6f28faf57a)
图12-11
解:(1)题图所示电路中,阻抗直接并接在A相电源上,对功率表的读数没有影响。求功率表读数电路如图12-12(a)所示,其单相计算电路如图12-12(b)所示。
图(a) 图(b)
图12-12
则可得:
V
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image552.png?sign=1739027667-17UyE6EetI05WAtOLdf3CIBIl5z2TPyl-0-88beb6f275da5ae5334f86dd2022eb2d)
功率表的读数为:。
(2)A相电源发出的有功功率:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image554.png?sign=1739027667-dmapwrs5ThTgDpa0Kab698QdWKc3G954-0-ac7447b445a069544380025884951ebb)
8.如图12-13所示三相四线制电路中,接有两组对称三相负载和一个单相负载。已知对称三相电源相电压为220V,第一组对称三相负载、
、
的大小。[同济大学2009研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image562.png?sign=1739027667-uKhW83J2ue6HWcGhTovMGCRXZ2s5KXYj-0-328e0b69de670ccc0978c8de2bafdd84)
图12-13
解:设A相电压为,则第一组对称三相负载的电流
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image564.png?sign=1739027667-qL6SM4RwmkFzmqFAJoVS6ME2Xr5QykK4-0-6ade8780025bae219e100ae20ad4764f)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image565.png?sign=1739027667-N6KcfjiUZ3DhsPTReLt13trvbMm3Hlnd-0-461b0d847276dc68d8514c979548ca15)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image566.png?sign=1739027667-W3rrIfta0fuFAWGIfA1d6vZgx3Rfynnc-0-af821cd5493d5d1afba2df9b2ed0232e)
假设负载为星型连接,则:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image567.png?sign=1739027667-Tafnb53Mc7quZsT4wFXQkxvJK8I6xF8J-0-4a51eb63cdea888959e06bf8cb7f7f51)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image568.png?sign=1739027667-M8ijpLEt8rxzoh0TFst3wT5f3pkMGRBJ-0-df6386ebcfac629bd4e1f93a8bda1bb4)
故第二组对称三相负载的电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image569.png?sign=1739027667-qA036Krer5AGRqZ7w9wNM8y3156VVkya-0-f0b7d6156f495a9fd5591848ca2a2252)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image570.png?sign=1739027667-S5urxnJETKM2avQzMZlNlrzSybz1NsUI-0-0b7187c8a6b0c3f17cea8d18aa448003)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image571.png?sign=1739027667-TtD32AgsBlo3UWpWaWCOelnqOCHIb2AV-0-4cab692231c0d073c5759970ea8340c7)
单相负载的电流:。
电源端线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image574.png?sign=1739027667-nvFO37cKYXlJKvDQQY8AtsXOD5TTZmu3-0-b31e51158416c1b68bb31717fa38e47c)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image575.png?sign=1739027667-a6z2Ks70jfY2AhlnyNacY1F2a5XfKXKv-0-8800e01d59cde5465307179a9f5b8787)
因此:,
,
。